When the transformer is operating at no load, the secondary winding is open-circuited, which means there is no load on the secondary side of the transformer and, therefore, current in the secondary will be zero. While primary winding carries a small current I_{0} called no-load current which is **2 to 10% of the rated current**.

This current is responsible for supplying the iron losses (hysteresis and eddy current losses) in the core and a very small amount of copper losses in the primary winding. The angle of lag depends upon the losses in the transformer. The power factor is very low and varies from** 0.1 to 0.15**.

The no-load current consists of two components:

**Reactive or magnetizing component I**_{m }(It is in quadrature with the applied voltage V_{1}. It produces flux in the core and does not consume any power).

**Active or power component I**, also know as a working component_{w}

(It is in phase with the applied voltage V_{1}. It supplies the iron losses and a small amount of primary copper loss).

The following steps are given below to draw the phasor diagram:

- The function of the magnetizing component is to produce the magnetizing flux, and thus, it will be in phase with the flux.
- Induced emf in the primary and the secondary winding lags the flux ϕ by 90 degrees.
- The primary copper loss is neglected, and secondary current losses are zero as

I_{2}= 0.

Therefore, the current I_{0}lags behind the voltage vector V_{1}by an angle ϕ_{0 }called the no-load power factor angle and is shown in the phasor diagram above. - The applied voltage V
_{1}is drawn equal and opposite to the induced emf E_{1}because the difference between the two, at no load, is negligible. - Active component I
_{w}is drawn in phase with the applied voltage V_{1}. - The phasor sum of magnetizing current I
_{m}and the working current I_{w}gives the no-load current I_{0}.From the phasor diagram drawn above, the following conclusions are made:

This is all about transformer in no load condition.

RAHUL ROYHow The Magnetizing Component (Im) can be minimised as done in Case of Motor By Capacitor Bank ????????????????………..

This Will Give relief From Paying Extra .

REply Requested

R SAI KUMARWe can minimize it by using high permeability core material.this is the region why we are using CRGO steel in transformer.

ADESIYAN ADEBAYO ABDULKAREEMWhy some transformers exitation current are low and why some are high.What is the required range subject their KVA rating.