A **synchronous motor** runs at **constant** synchronous speed, regardless of the **load**. Let us see the effect of the load change on the motor. Consider a synchronous motor operating initially with a leading power factor. The **phasor diagram** for the leading power factor is shown below:

The load on the shaft is increased. The rotor slows down momentarily, as it required some time to take increased power from the line. In another word, it can be said that even if the rotor is rotating at synchronous speed, the rotor slips back in space because of the increase in the load. In this process, the torque angle δ becomes larger, and, as a result, the induced torque increases.

The induced torque equation is given as:

Then increased torque increases the rotor speed, and the motor again regains the synchronous speed, but with the larger torque angle. The excitation voltage E_{f} is proportional to ϕω, it depends upon the field current and the speed of the motor. Since the motor is moving at a synchronous speed, and the field current is also constant. Hence, the magnitude of the Voltage** |E _{f}|** remains constant. We have,

From the above equations, it is clear, that if P is increased the value of E_{f} sinδ and I_{a} cosϕ also increases.

The figure below shows the effect of an increase in load on the operation of a synchronous motor.

It is seen from the above figure that with the increase in load, the quantity jI_{a}X_{s} goes on increasing and the relation** V = E _{f} + jI_{a}X_{s} is satisfied**. The armature current is also increased. The power factor angle also changes with the change in load. It becomes less and less leading and then becomes more and more lagging as shown in the figure above.

Thus, if the load on a synchronous motor is increased the following points are considered which are given below.

- The motor continues to run at synchronous speed.
- The torque angle δ increases.
- The excitation voltage E
_{f }remains constant. - The armature current I
_{a}drawn from the supply increases. - The phase angle ϕ increases in the lagging direction.

There is a limit to the mechanical load that can be applied to a synchronous motor. As the load is increased, the torque angle δ also increases until the condition arises when the rotor is** pulled out of synchronism** and the motor is stopped.

**Pull-out torque** is defined as the maximum value of the torque which a synchronous motor can develop at rated voltage and frequency without losing synchronism. Its values vary from **1.5** to **3.5** times the full load torque.

GunjanPower-factor of m/c also decrease in case of normal and under excited conditions?

Abhilash Mukherjeeyes definitely

Sujoy Chatterjeeyes. the power factor angle increases and hence power factor decreases in under excited or lagging case of synchronous motor. but in b l Theraja, it is wrongly stated that PF increases in under excited case. which is completely wrong.

AlawiThanks for the insightful material. Can you recommend some books for more in depth information on this topic?